I am a newbie electronics students.
My question is, what does it mean (what happens) when you connect pin 2 to pin 6 on a 741 op. amp., meaning the inverting input to the output (just a jumper cable).
For some reason my circuit works now when I did it, I just did it on accident. Nothing is connected to pin 2, not ground or anything, just pin 6. To pin 6 it's just pin 2 and another cable just to measure the output compared to ground.
Of course I have some other stuff connected to the op. amp., which is a variable resistor voltage divider to pin 3, -15V to pin 4 and +15V to pin 7.
My assignment is to find a linear relationship between the distance to a light source (using a LDR), and the output voltage (or current) of the op. amp.
But yeah, if someone knows anything about my question that would be really helpful, I will probably rebuild my circuit though.
I'm using a myDAQ if that's relevant.