I have half a meter of 18 AWG (1.02mm diameter) stranded copper wire and I am planning to run 12 volts with a maximum 6 amp load.
Determining the cross sectional
area = 0.51mm^2 * PI, gives me ~
Determining the resistance
R = (1.72e-8 * 0.5 meters) / area, gives ~
0.0105 Ohms resistance for the half meter length.
My attempt to then determine voltage drop is
V = I * R,
V = 6 * 0.0105, giving a voltage drop of ~
Why then do many online calculators have a multiplier of
2 on this drop? (~