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I have seen this circuit on internet. I would like to understand what its purpose is.

It seems to be related to something which is call "jitter." I have done some research about "jitter" and I think that I have understood what it is. However I do not understand the circuit below and particulary how it works with its double feedbacks (positive and negative.)

enter image description here

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  • \$\begingroup\$ Where did you find it? Jitter doesn't occur by itself. \$\endgroup\$
    – JRE
    Commented Dec 12, 2019 at 18:22
  • \$\begingroup\$ Looks to me like some kind of filter. \$\endgroup\$
    – Hearth
    Commented Dec 12, 2019 at 18:23
  • \$\begingroup\$ Have you tried running a simulation? \$\endgroup\$ Commented Dec 12, 2019 at 18:26
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    \$\begingroup\$ A badly transcribed relaxation oscillator. As it stands it wouldn’t work. \$\endgroup\$
    – Andy aka
    Commented Dec 12, 2019 at 18:31

1 Answer 1

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In order to get this Relaxation Oscillator or any for that matter, is to have both inputs Vin+- to have the same swing and average voltage for a 50% square wave.

This means if the output swing is. 2 to 13V for BJT type OA or 0 to 15 V for a CMOS then the Vref. Input must be Vcc/2 and not 15V as shown. Then you get 50% duty cycle. Any change in this offset changes the duty cycle.

The Voltage divider Vout to Vin+ thus determines the swing from this average voltage. What is shown is 3.3/(3.3+1) or about 3/4 full swing exponential triangle. Now the CMOS Schmitt Inverter OSC uses a hysteresis of 2/3 full square swing for the triangle..

Then with +/- 1/3 swing same as the 2/3 hysteresis, the ramp is fairly linear but instead of 64% it is 66% but depends on tolerances with slight exponential response T=RC for f~ 1/2T. Reducing the hysteresis increases the frequency just like changing the RC value.

SIMULATION

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