I know this question was asked before, But couldn't understand properly the datasheet reading.
I would like to control water pump
via RPI
.
Wanted to make sure Im reading the datasheet correctly + Im connecting everything properly.
So if I understand correctly, on the worst case, the water pump will need 6v. so the calculations will be according to Ipump(max)
Ipump(max) = 1.8w/6v = 300mA
Ipump(min) = 0.6w/4v = 150mA
According to 2N2222
data sheet, figure 11:
When Ic=300mA
, Vbe(sat)=0.9v
and hfe=10
.
So:
Ib = Ic/hfe -> 300m/10 = 30mA
R1 = (Vrpi - Vbe)/Ib -> (3.3-0.9)/30m = 80ohm
In order to make sure the water pump will get the current it needs, we will limit Ic
to higher value:
R1=50ohm
Ib=(3.3-0.9)/50= 48mA
Ic=Ib*hfe= 48m*10 = 480mA
So R1=50ohm
Wanted to ask :
1. Do I read the `hfe` correctly? is it the right value to make sure the saturation?
2. There is a need to connect a diode in parallel to the water pump? resistor in series to the water pump?
Thanks for the guidance.