# Does a radio antenna need to form a closed loop to function?

In either a radio transmitter or antenna, is the antenna and open end or a closed loop?

In electrical theory it seems that no open loop could achieve anything. But in physics a piece of metal exposed to radio frequencies might be expected to vary in electrical potential in a way that a sensing system (tuner) could be sensitive to.

Similarly with a radio tower, is the tower an open-ended conductor whose electrical potential is rapidly varied, or does the tower only emit radio waves when it conducts a current along its length?

• Given that we can communicate with rockets in space without any apparent closed loop circuit, you should be able to answer that yourself maybe. Apr 1, 2021 at 12:59
• @Andyaka good to hear from you! I think the question is misunderstood. Does the emitter need to be in itself a closed loop to make meaningful radio waves, and equally the receiver antenna need 'two ends' for the tuner circuit to gather any useful electrical signal? I think if the emitter and receiver needed to be electrically linked then we'd probably still have steam engines..! Apr 1, 2021 at 13:03
• Half-wave dipole is not a loop. Apr 1, 2021 at 13:04
• Thank goodness that speed-of-light limits how electrical currents propagate along a conductor. Current at one point can differ from current at a different point - especially so at high frequencies where wavelengths shrink. Only at low frequencies can we make the assumption that current is the same everywhere along a wire path - in this case current paths must return to source. Apr 1, 2021 at 13:13
• @glen_geek This is the thinking I'm going with. However it seems that an open loop emitter would have a significant power limit compared to a closed loop emitter of similar mass. Would you agree? Apr 1, 2021 at 13:15

An antenna of the classical type (such as a quarter wave monopole) appears to have an open end and therefore, current flowing in the monopole must become zero at that open end. This kind of implies that no current can flow but that isn't the case. A monopole requires the presence of ground/earth to work effectively and, it is the capacitance to ground that allows current to flow in a seemingly open-wire. Of course that current has to be AC just as a capacitor requires an AC voltage across it for current to pass through it.

It also needs to be roughly the right sort of frequency compared to the physical size of the antenna to transmit or receive radio waves effectively.

Yet real current (electrons) do not pass from one capacitor plate to the other; the action of charge building up on one plate ejects charge from the other plate and current is "seen" to flow through the wires of a capacitor. What flows between the plates is called "displacement current". Displacement current has all the same hallmarks as a real flow of electrons without electrons being harmed in any way. That displacement current produces a magnetic field just as a real flow of current does.

So, when we have a monopole excited with an AC source, there are magnetic and electric fields produced that surround the antenna. Those fields can be quite complex close to the antenna but, at some small distance from the antenna can resolve into values that match the impedance of free space (approximately 377 Ω). That creates a radio (EM) wave that propagates at the speed of light. In fact light is an electromagnetic wave and it propagates through space using the same medium as radio.

A dipole antenna is two quarter wave monopoles and doesn't require an earth/ground because it is driven differentially and, it is the capacitance from one end to the other that is important: -

Picture from here

And, when receiving: -

Picture from here

With both dipole and monopole antennas, if you match the applied frequency to the length of the antenna you can efficiently convert electrical power in the feed wires to radiated power in free-space (vacuum or air for instance).

• I suppose the usual question in electronics is 'relative to what?' When driving an open loop transmitter, lets say you are creating a - 50 kV signal in the antenna. But given there is an open loop, it is 50 kV with respect to what? The ground local to the station? Earth on the nearest supply? (Could be the same thing I guess) Apr 1, 2021 at 13:33
• If it's a monopole then it's relative to ground. If it's a dipole, then it will be relative to the two ends of the dipole. Apr 1, 2021 at 13:34
• If with respect to ground, then lets say the space station is communicating with earth, the antenna would have to be emitting with respect to the body of the station. I imagine this would make all sorts of noise and interference in the station. Apr 1, 2021 at 13:36
• The word "capacitor" is sufficient to refute the question's assertion that "no open loop could achieve anything"! Apr 1, 2021 at 13:39
• @JCollins a dipole antenna needs no connection to local ground and neither do dish antennas. Apr 1, 2021 at 13:40

When you first learn electrical theory you deal with things that are physically small, so you don't have to think about how electrical signals radiate outside of conductors and devices. In that setting you need closed loops. But when the size of a circuit element is roughly the same as the size (typically measured in meters or, for higher frequencies, centimeters) of the waves that you're dealing with, that small-circuit simplification no longer applies. One common form of antenna is a half-wave dipole, which is not a closed loop. There are loop antennas, which, as the name suggests, are a closed loop.