3
\$\begingroup\$

I am using this MEMS microphone for a stethoscope project. The data sheet recommends the following interface circuit.

I can't seem to find where it states specifically that it is a differential output instead of a single-ended one. Am I right in understanding it as outputting a differential output?

enter image description here

\$\endgroup\$
5
  • \$\begingroup\$ The mic (the piece of hardware) is only the circle with mic. Rest is hardware outside the component. Like the recommended one. \$\endgroup\$
    – RemyHx
    Commented Dec 12, 2022 at 7:28
  • \$\begingroup\$ Do you intend to use an analog one? Or a digital? \$\endgroup\$
    – RemyHx
    Commented Dec 12, 2022 at 7:28
  • \$\begingroup\$ Is there both, I am under the impression that the mic only output analog. I plan to feed it into a analog filter. \$\endgroup\$ Commented Dec 12, 2022 at 8:49
  • 1
    \$\begingroup\$ Feeding straight into a differential opamp from capacitors is asking for trouble. There needs to be biasing and feedback. So, the diagram is illustrative only \$\endgroup\$ Commented Dec 12, 2022 at 13:46
  • \$\begingroup\$ Hi again, I am glad you found an analog-output MEMS mic but the Chinese manufacturer does not know the details of an opamp. The other website with your heartbeat project was down. \$\endgroup\$
    – Audioguru
    Commented Dec 12, 2022 at 18:10

1 Answer 1

1
\$\begingroup\$

It is a single ended output, see just one "OUT" pin, even if they don't explicitly say so. If it were a differential output, there would be an "OUT+" and an "OUT-" pin.

What they have shown is their recommended way to connect to a differential-input amplifier, and to be honest I'm not completely happy with how they show that (there seem to be a lot of unstated assumptions).

I am surprised they didn't show, instead or as well, a simpler recommended connection to a single-ended-input amplifier... like a series DC blocking capacitor going to a the input of an amplifier, pulled to (the amp's) mid-rail by a high value resistor. Signal ground would be shared between the MEMS and the amplifier.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.