I am a beginner my self but I will try to answer your question. First some rules. For transistor to be in active mode of operation \$V_B - V_E = V_{BE}\$ must be larger then \$0.6V\$ and \$V_{CE}\$ must be larger then \$0.2V\$ and \$V_B < V_C\$.
I suppose that at your picture \$R_E\$ is grounded. Now think what happens when you apply sinusoidal signal that has amplitude of \$500mV\$. Transistor will not work \$500mV < 0.6V\$. Now suppose you increase amplitude to \$2V\$. What happens when signal is negative? \$V_B\$ is lower than ground and transistor will turn off. No current will flow to collector or from emitter. So you will get rectified sinusoidal signal.
The problems in you circuit is that transistor turns off when input signal if very small or negative. Two solutions. Connect negative supply to \$R_E\$ for example \$-V_{cc}\$. Or bias the base. Biasing the base means setting some positive dc voltage at it. You can do it using voltage divider.
So you must connect voltage divider output to base. The picture of the circuit can readily be found by searching for common emitter amplifier using google. You will see capacitor in those circuit. They are just used to remove the dc values from the signal so that the small signal will not affect biasing.
