2
\$\begingroup\$

The vector potential in magnetic field (represented by A), what does that physically mean? I have serious problem in understanding it intuitively.

$$\nabla^2\text{A} = -\mu_0 \text{j}$$

I read that the above equation can be derived using continuity equation. Can it be derived? if possible how? Thank you.

\$\endgroup\$

1 Answer 1

Reset to default
2
\$\begingroup\$

The short answer is the vector potential is such that the curl of it gives the B field. (Taking a curl is often easier than integrating.) There is also a fascinating quantum mechanical effect, such that the vector potential leads to a phase change of particles. I went looking on line and it's hard to beat the Feynman lectures. Enjoy!

\$\endgroup\$
1
  • \$\begingroup\$ I read through the whole lectures of feynman found it really helpful and got to know about the derivation too.thank u \$\endgroup\$
    – ArAvind
    Commented Dec 17, 2015 at 15:09

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.