Is there an easy way to convert TTL/CMOS output signals to 0 and 5V? For example, if an ic outputs 0.1V as "0", I'd like to convert it to 0V and if it outputs something like 3.9V as "1", I'd like to convert it to +5V. Thanks.
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4\$\begingroup\$ Not enough detail. What's the load? What's the speed? And why? \$\endgroup\$– TransistorCommented Jun 29, 2017 at 21:31
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1\$\begingroup\$ How close to 0V and 5V is good enough? \$\endgroup\$– brhansCommented Jun 29, 2017 at 21:38
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\$\begingroup\$ VTC of an inverter courseware.ee.calpoly.edu/~dbraun/courses/ee307/F02/02_Shelley/… is worth understanding as the general theory applies to all logic gates. As a bonus the VTC is for a 5V gate, readoff 3.9V input as a sample. \$\endgroup\$– sstobbeCommented Jun 29, 2017 at 21:42
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1\$\begingroup\$ Use a Level Translator such as electronics.stackexchange.com/a/97892/35022 \$\endgroup\$– MarkUCommented Jun 30, 2017 at 0:00
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2\$\begingroup\$ "Normal" digital logic families are very tolerant with regard to input voltage levels. For example old TTLs will read anything below 0.8V as a low, and anything above 2V as a high. I doubt you'll have any trouble driving an arduino shield directly from a Z80 device. \$\endgroup\$– brhansCommented Jun 30, 2017 at 12:11
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Generally a CMOS buffer, or two inverters in series, will do what you ask when powered from a precise reference supply. Anything more than 0.7 Vdd will give you a high output, and anything less than 0.3 Vcc will give you a low. Both will be very close (millivolts) to the supply rails if there is little loading. If you need to accommodate lower inputs you can use something like a voltage translator, an HCT gate or even a CMOS LVDS receiver.
For more current and little voltage drop you can use a CMOS-output MOSFET gate driver- some of them can drive very high currents and have an output resistance in the ohms rather than more like 100 ohms+.
Using a precise 5V reference for the buffer supply and feeding it a 5V-ish digital PWM input can give you a precise analog voltage when filtered.
answered Jun 30, 2017 at 1:34