Switch a 12 VDC circuit from a 0.6 volt signal

Question

I need to switch a 12 VDC circuit (automotive ignition coil) with a .6vdc signal from an impulse coil. I am trying to replace the ignitor box for this engine; they are extraordinarily expensive and cannot be tested. From what I have read, this may require a germanium transistor to increase voltage sufficiently to perhaps use a MOSFET for the twelve volt circuit. This ignition system fires the ignition coil by interrupting the path to ground for the primary circuit of the ignition coil as opposed to the circuits with which I am familiar, i.e., interrupting the power side of the primary coil. I know just enough about electronic circuits to get into trouble.

Not a model t; oddly enough, I would have no trouble with that; I've worked on many. No, this is an EZGO utility cart I use around our property with a two cylinder Robin engine, 9 HP. I am disabled and depend upon this cart greatly. I understand the circuit diagram provided, thank you.
The impulse coil by factory spec is from 433.5 to 586.5 ohms. The primary winding resistance of the ignition coil is negligible; 0.5 ohms according to my meter. I understand the output would be weak; would it be sufficient to drive a MOSFET (or similar switching device) that would provide a ground path for the ignition coil? I really expected a much higher output from the impulse coil, but that is why I am asking experts. Thank you very much for your help and responses.

Answer 1

Consider thisl note the output has only a WEAK drive ability.

^{simulate this circuit – Schematic created using CircuitLab}

The circuit will provide almost rail-rail output, using the impulse coil, which I assume is just about a short (< 100 ohms).

Or you could use a comparator that accepts inputs as low as GND. Some older ICs with PNP inputs perform quite well.