0
\$\begingroup\$

How to cut AC source using DC Bias (MOSFET or TRIAC or optocoupler)? Is that possible? I use this circuit, but looks like the AC source not cut off or fully short. enter image description here

Btw, this is secondary side from WPT, I want to cut or short the AC source by change the resonant value (you can see there is capacitor there that connect with optocoupler).

Thank you.

\$\endgroup\$
2
  • 2
    \$\begingroup\$ Welcome! What do you mean by "cut AC source"? What's your goal? \$\endgroup\$
    – winny
    Commented Aug 22, 2023 at 7:02
  • \$\begingroup\$ You may need a separate source. \$\endgroup\$ Commented Aug 22, 2023 at 7:29

1 Answer 1

0
\$\begingroup\$

I want to cut or short the AC source by change the resonant value

WPT (wireless power transfer) uses quite high resonance to achieve decent (sufficient) power levels in the receiver so, a simple opto just won't cut-the-mustard when used as a switch on the AC output of the receive coil. At the very least you need a more powerful device such as a MOSFET and, this can shift the receiver tuned circuit's resonant frequency by a reasonable amount.

However, because you are trying to "re-tune" an AC circuit, you would use back-to-back MOSFETs wired as a solid-state relay (SSR) to achieve this. There are devices available that can do this (if you just want to move the resonant frequency enough to detune the receiver a bit) but, if you want to "cut" the receiver's coil signal completely I believe you are going to be unlucky. Reason: as soon as this is "cut", the receiver loses power and inevitably "un-cuts" the solid-state-relay and power is restored again.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.