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Using a microcontroller timer, is it possible to produce the following signals:

enter image description here

With the following constraints:

  • use only one timer (can count up or down or up and down)
  • output compare channel has only one comparison register
  • no software interactions after the initial setup

I don't want to couple the question to any particular MCU, but you can think of STM32 timers as an example.

I would say it is not possible, but maybe I am not seeing some clever register configuration.

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  • \$\begingroup\$ Unlikely with the restrictions you have. However there might be a MCU with special abilities that makes it possible. Such as programmable logic. \$\endgroup\$
    – Justme
    Commented Sep 15 at 8:15
  • \$\begingroup\$ Some TI C2000 microcontrollers contain a Configurable Logic Block (CLB). The application report How to Migrate Custom Logic From an FPGA/CPLD to C2000™ Microcontrollers gives an overview of the capabilities. Posting as a comment to give a suggestion, and not an answer, as haven't checked if will meet all the constraints. \$\endgroup\$
    – Chester Gillon
    Commented Sep 15 at 8:23
  • \$\begingroup\$ At what frequency would you these signals? \$\endgroup\$
    – Antonio51
    Commented Sep 15 at 12:25
  • \$\begingroup\$ @Antonio51 Why would it matter? At any frequency supported by the timer. \$\endgroup\$
    – user930473
    Commented Sep 15 at 13:11
  • \$\begingroup\$ Then, simple timer working under interrupt and outputting 2 signals in one defined byte (b00011110) would do it (shifting 2 bits, 4 x). \$\endgroup\$
    – Antonio51
    Commented Sep 15 at 13:46

1 Answer 1

Reset to default
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If the signal is not high-frequency, within 1-1000 Hz, you can try to reinitialize the comparison register and the timer polarity in the interrupt callback function "on the go".

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  • \$\begingroup\$ That idea is against the "no software interactions" so it does not qualify. \$\endgroup\$
    – Justme
    Commented Sep 15 at 18:50

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