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I'm currently trying to learn how binary adders work, but I don't understand what a "carry in" is for. What is the purpose of a "carry in"?

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3 Answers 3

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It's important to understand there's a difference between a half-adder and a full-adder.

A half-adder is the simplest. It has 2 inputs and 2 outputs. It's basically a XOR.

The primary output is only 1 if one of both inputs is 1, but not if both are 1. That's Sum. The second output is only 1 if both inputs are 1. That's Carry.

That's nice, but only if you're adding two bits. If you need more bits, you'll have to combine some adders together. Here's where full-adders come into play. The Least Significant Adder is a half-adder, and every More Significant Adder will be a full-adder which will take the Carry of the previous adder.

A   B   Cin     Cout    Sum
0   0   0       0       0
1   0   0       0       1
0   1   0       0       1
1   1   0       1       0
0   0   1       0       1
1   0   1       1       0
0   1   1       1       0
1   1   1       1       1

(shamelessly copied from Wikipedia)

If Carry in is 0, the behaviour of a full-adder is identical to a half-adder.

However, if Carry in is 1, the behaviour of Sum is inversed and the behaviour of Carry out changes into a OR. As long as any of the inputs is 1, Carry out is 1.

Carry in is required to turn a basic 2-bit adder into a multiple-bit counter. That's the purpose of Carry in.

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    \$\begingroup\$ With twos complement format (-x == ~x + 1), the carry-in can also be used for subtraction (inverting the subtrahend and setting the carry-in negates the value which can then be added). \$\endgroup\$
    – user15426
    Commented Jul 24, 2015 at 0:21
  • \$\begingroup\$ @PaulA.Clayton Technically that would be a subtractor. I had the idea that would provide an information overload for OP, there is much more information to share about this matter. \$\endgroup\$
    – Mast
    Commented Jul 24, 2015 at 0:32
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    \$\begingroup\$ Avoiding info-dumps can be difficult for some people (like me); your judgment is probably correct. \$\endgroup\$
    – user15426
    Commented Jul 24, 2015 at 3:06
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Besides what is said by those who replied earlier, Carry can also mean an input coming from the flag register that allows linking one sum on a ALU to the next one. By linking I mean that, if your computer architecture has a ALU with a word size of 8 bits and you need to do a 16 bit sum, the ALU can use the Carry flag, placing it on its carry in as a way to allow the processor to continue the sum from the previous one. This allows two 8 bit sums to become a single two step 16bit sum.

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The purpose of the "carry" in is to accept the "carry" out of the previous adder. Carry works just like normal arithmetic.

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