I am trying to find the inductance of a inductor. I have tried many different methods such as putting the inductor in parallel with a capacitor to form a tank circuit and in series with a resistor with 1% tolerance.

The specific sites I used are:




Problems I encountered with links 1) The oscilloscope I use outputs voltage/div. I do not have a current probe.

2) When I run a sine wave, or any wave form, from the function generator. The waveform I see on the oscillator is the same wave I used from the function generator; Same frequency.

3) No option to adjust current output from function generator.

4) My oscilloscope outputs a normal sine wave. I don't see a decreasing/increasing sine wave.

5) I know that the readings are wrong because when I switch capacitors, the math shows that the inductance has changed. I have a fixed inductor that I used to test also.


Other stuff to mention:

The oscilloscope I am using


The function generator I am using


  • 2
    \$\begingroup\$ Well, if you apply a sine wave to a linear circuit, you will see that same sine wave (perhaps with different phase and amplitude) anywhere in the circuit. This is a universal property. To answer your other questions, a circuit is needed. \$\endgroup\$ Apr 1, 2016 at 10:11

1 Answer 1


1 you do not need a current probe. Put an ohmic resistor in series with inductor and measure the voltage over the resistor

2 capacitor and inductor do not change an input sine wave, only the amplitude and phase

3 not much to say

4 where are you putting your oscilloscope probe? Put a series resistor with your inductor and try to read over the inductor. If the sine keeps the same, maybe your inductor has a low inductance. Try to lower the frequency of the sine generator

  • \$\begingroup\$ Thanks for the respond. I will give this a try. Also, what do you mean by tension? \$\endgroup\$ Apr 2, 2016 at 1:54
  • \$\begingroup\$ Sorry, I mean voltage \$\endgroup\$
    – Amadeus
    Apr 2, 2016 at 1:58
  • \$\begingroup\$ Please edit your answer. \$\endgroup\$ Feb 2, 2018 at 22:37

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