Finding the necessary currents for AC analysis for CE NPN BJT amplifier

Question

I have this circuit with a CE NPN-BJT amplifier and I am struggling to find the necessary values for calculating r(pi) for AC analysis, i.e. the hybrid-pi model:

$$r_{pi} = \frac{V_{thermal}}{I_b}$$

I need to find the current going into the base of the CE amplifier. I am assuming that the infinite capacitance to be short circuited in the DC analysis. This means that V(b) = 0 I can then use the active region model of NPN BJT for DC analysis to write down the KVL which gives me something like this: -0.7 - 60(I[e]) = 0

I solve the equation and end up with a negative emitter current. This does not adhere to the model. What am I doing wrong?

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Answer 1

@vtolentino already got it right in the comments: in DC analysis all capacitors are open-circuited, it should be fairly simple to find what you want after that.

I'd like to add that this BJT is not a Common-Emitter BJT, it's a Common-Base BJT because the base terminal is common to both inputs and outputs, so you're dealing with a CB NPN-BJT.