I want to build an analog front-end with a 16 channel multiplexer. On each multiplexer input, there will be a voltage divider made from resistors. On the multiplexer output, there will be an op amp buffer and later on an ADC. The signals are low frequency <100Hz.
simulate this circuit – Schematic created using CircuitLab
Now what I'm concerned about is the offset introduced by the multiplexer due to leakage current. So for selecting the right part, I will need to make some calculations about the worst-case offset. I already have the correct formulas by hand. However, what confuses me is the specifications in the datasheet:
Here's an example of the MUX506IPWR multiplexer from Texas Instruments:
The datasheet specifies three different leakage currents. I am interested in the leakage that occurs for a particular channel during measurement (when the switch is on). So initially, I though that I just have to consider the Output on-leakage \$I_{D(ON)}\$. Then I noticed that they use the term "switch".
Since a 16 channel multiplexer contains 16 switches (only one can be active at a time, and all switch outputs are connected) do I also need to consider the Output off-leakage \$I_{D(OFF)}\$ in my calculations? e.g.: $$total\ leakage\ current = 15 \cdot I_{D(OFF)} + I_{D(ON)}$$ or is this somehow already contained in the specifications of \$I_{D(ON)}\$?