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I'm building a linear power supply. The first stages are all working great. Coming out of the rectifier and filter caps, I have 28V DC. I also have a voltage reference circuit (LM317) that gives me a stable 14V.

Here's a schematic of what I have so far:

schematic

simulate this circuit – Schematic created using CircuitLab

I now want to add the regulation circuit for the output transistors. Similar to a power supply I built before, I was just going to use an op amp to drive the output transistors (probably through a high current buffer) so the output voltage matches the reference voltage. I also had a transistor for current limiting, like this:

schematic

simulate this circuit

However, that would require me powering the op amp off of 28V (under no load), and the most any of the op amps I have can handle is 22V supply. I'm figuring I can't run the op amp off of the 14V line since its output will likely need to be higher than 14V to drive the output transistor.

I could buy other op amps, but I'm curious if I can get by with what I have.

I know I could just make a step down circuit to power the op amp, but I'm thinking there has to be a more elegant solution. Is there a more elegant/better solution?

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  • \$\begingroup\$ Why not use your 14V to power the opamp? \$\endgroup\$
    – John Doty
    Commented Jan 11 at 5:59
  • \$\begingroup\$ byl, can you show the power supply you built before? And how much current compliance are you considering? \$\endgroup\$ Commented Jan 11 at 6:15
  • \$\begingroup\$ @periblepsis what do you mean by current compliance? \$\endgroup\$
    – byl
    Commented Jan 11 at 17:24
  • \$\begingroup\$ How much output current do you need? And what power transistor do you want to use? \$\endgroup\$ Commented Jan 11 at 17:47
  • \$\begingroup\$ @byl What Jonathan just asked -- current compliance just means what's the maximum current that might be required of the supply? \$\endgroup\$ Commented Jan 11 at 17:58

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Reconsider a derived power supply for the opamp. If the Power Q is a darlington, the opamp needs only 5 to 10 mA of operating and output current. This can be done with 1 zener diode, 1 resistor, and 1 noise filter capacitor. 50 cents? You don't show a power supply decoupling capacitor for the opamp, but it already should be a part of the control schematic.

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  • \$\begingroup\$ I hadn't realized the current draw would be so low. A zener diode would be easy then... \$\endgroup\$
    – byl
    Commented Jan 11 at 20:12

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