A EDIT: SONY camera release cable is usually designed to short two terminals (+5V EDIT: 3.17V, 0V) when the button is pressed, as shown in the following figure.
These two terminals also lose their voltage difference when a button on the camera body is pressed.
EDIT:
- When the camera is turned on and the switch is not pressed, a potential difference of 3.18 V is generated, and when the switch is pressed, a potential difference of 4.5 mV is generated.
- When the camera is turned off and the switch is not pressed, the potential difference is unstable, and when the switch is pressed, the potential difference is 0.0mV.
Therefore, I connected the terminals as follows so that when a button on one camera body is pressed, the shutters on all cameras are released. This actually works.
However, I thought that the potential difference between Shutter1 and Shutter2 might cause a current to flow in the opposite direction, which might adversely affect the camera with lower voltage.
EDIT: In my situation comparing the two fully charged SONY α7, when two GNDs are shorted with crocodile clips, the potential difference is 0.2 mV and 0.2 µA flows when neither button is pressed, 136.9 µA when camera 1
button is pressed, and 138.6 µA when camera 2
button is pressed.
Thus I came up with the following circuit, will this work correctly? I am quite unsure as I am not familiar with electronic circuits.
The following solution is available as described here, but I would like to avoid this one because it requires an external button.
I modified the question and posted it on photo.stackexchange.com as well following this guideline.