0
\$\begingroup\$

I try to design a circuit that adds two 4-bit binary numbers, but I get confused about the carry thingy.

enter image description here

Above I add 0100 + 0101. The result should be 1001, but it shows 1100. buzzer

Later I did the 0110 + 1001 and it got it right (1111).

Then I tried 0111 + 0010 and I got 11010. buzzer

Is it the Half Adder fault?

Did I falsely connect each carry to the "CIN"s?

What's wrong?

\$\endgroup\$

1 Answer 1

1
\$\begingroup\$

Your switches are arranged LSb to MSb, but you're inputting the numbers MSb to LSb. Your schematic shows 0b0010 + 0b1010, with a correct result of 0b1100.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.