Why does DIV AB converts from hex to decimal 8051

Question

I was trying to solve a problem and I read that this code converts a number from hex to decimal I mean why . My idea is that div is just for division can somebody answer my questions that I left as comments

MOV A,#0FFH ;why do we need to do this MOV P1,A ;P1 as an INPUT MOV A,P1 ;Get data from P1 MOV B,#10 ;to convert from hex to decimal DIV AB ;that the question why does div used to do this conversion MOV R7,B ;does this put 10 in the register r7 MOV B,#10 DIV AB MOV R6,B ;it does also puts 10 in the register r6? MOV R5,A ;if A <10 (why does this do )

Answer 1

Simple enough

A starts out being a number between zero and 255.

Lets say its FF i.e. 255..

Dividing by 10 gets you 25 in A and 5, the remainder, in B. That's the units value, so we save B to R7

Next we setup B with 10 again and divide the 25 by ten, and again store the remainder, this time in R6, as the tens digit.

What is left in A is the hundreds count, and we store that in R5.

So.. R5,6, and 7 now contain 2,5,5, the decimal equivalent of FF.

Here is a register trace if it helps..