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Just wondering what's the wiring, kinda confused on how this actually looks on a schematic.

enter image description here

Does this look correct?

schematic

simulate this circuit – Schematic created using CircuitLab

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    \$\begingroup\$ You could always read the rest of the datasheet. \$\endgroup\$ Commented Oct 31, 2018 at 4:19
  • \$\begingroup\$ I did, I never got onto anything \$\endgroup\$
    – Leoc
    Commented Oct 31, 2018 at 4:27
  • \$\begingroup\$ Perhaps if you know what the difference between a potentiometer and a rheostat is, it would help. \$\endgroup\$
    – TimWescott
    Commented Oct 31, 2018 at 4:53
  • \$\begingroup\$ Oh interesting, so its just a single variable resistor? \$\endgroup\$
    – Leoc
    Commented Oct 31, 2018 at 5:45

2 Answers 2

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It's a (simulated) variable resistor between pins 5 and 6. From Wikipedia:

enter image description here

Of course there are some differences with real resistor, such as the requirement that both ends of the resistor must always remain within the power supply rails of the chip for proper operation. The "wiper resistance" is in series with the "element resistance" which means some nonlinearity that will vary with voltage of the simulated rheostat and the supply voltage.

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  • \$\begingroup\$ How would one use it in a feedback loop in an amplifier, to automate gain? \$\endgroup\$
    – Leoc
    Commented Oct 31, 2018 at 17:39
  • \$\begingroup\$ You could use it as the feedback resistor in an inverting amplifier, in conjunction with a fixed resistor R. Gain = -Rf/R. Or swap resistors so you get 1/gain proportional to Rf. Etc. But it will likely introduce some distortion. \$\endgroup\$ Commented Oct 31, 2018 at 17:52
  • \$\begingroup\$ Would it be too much to see a schematic on how its hooked up? I am confused on the wiper pin because I want to use an arduino to control the resistance values \$\endgroup\$
    – Leoc
    Commented Oct 31, 2018 at 18:05
  • \$\begingroup\$ This sounds like a new question- it will have to get int design of a single supply amplifier probably, so more than just this question scope. \$\endgroup\$ Commented Oct 31, 2018 at 18:50
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Yes you are right.

you can find on page 2 of the datasheet this schema :

enter image description here

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