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I am making the assumption that a loop antenna is essentially an inductive loop and behaves as such, please let me know if this is incorrect.

Knowing that the voltage (emf) across an inductor is proportional to the rate of change of magnetic field, why when we measure the voltage from a magnetic loop antenna are we not measuring the rate of change in time of the magnetic field rather than the magnetic field magnitude directly?

I am trying to understand the difference between conventional loop antennas and B-dots (magnetic differential field probes) but the physics seems to be the same.

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Why does a loop antenna not measure the differential magnetic field?

Electromagnetic waves, when they are far from the source, and far from electrically conductive or ferromagnetic materials, have electric field and magnetic field components that are related to one another by the relationship

$$E = \sqrt{\frac{\mu}{\epsilon}}H$$

It is only in "near fields" that the \$E\$ and \$H\$ components can vary independently.

So, when one is measuring a "far field" it doesn't matter whether one measures the \$E\$ field, or the \$H\$ field, or some combination of the two.

When one is measuring a "near field", with a loop antenna, the type of loop antenna makes a difference.

There are "small" loop antennas and "large" loop antennas. The "large" variety have a loop perimeter that is approximately one wavelength of the frequency of interest. The "small" variety have a loop perimeter that is less than one half of a wavelength.

The "large" loop antennas have peak radiation (or reception) directions that are perpendicular to the plane of the loop. The peak radiation (or reception) directions of a "small" loop antenna are along the plane of the loop.

Now, importantly for your question, when a small loop antenna is receiving, it is driven more by the magnetic field than by the electric field, whereas a large loop antenna is driven by both electric and magnetic fields. A small loop antenna with a ferromagnetic core, known as a "loop stick", is almost exclusively driven by the magnetic field.

So, the answer to your question

Why does a loop antenna not measure the differential magnetic field?

The answer is, it can, if it is the right sort of loop antenna (i.e. "small" in relation to the wavelength). It will especially do so if it is a loop-stick antenna.

I am making the assumption that a loop antenna is essentially an inductive loop and behaves as such, please let me know if this is incorrect.

That is not correct for large loops. The get part of their energy from the H field, and part from the E field.

Knowing that the voltage (emf) across an inductor is proportional to the rate of change of magnetic field, why when we measure the voltage from a magnetic loop antenna are we not measuring the rate of change in time of the magnetic field rather than the magnetic field magnitude directly?

When you measure the voltage at the feedpoint of a small loop antenna, you are measuring the rate of change of the magnetic field, rather than its instantaneous value.

I am trying to understand the difference between conventional loop antennas and B-dots (magnetic differential field probes) but the physics seems to be the same.

Magnetic differential field probes are very "small" (relative to wavelength) loop antennas. So the effect of the electric field on them is "small" as well.

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  • \$\begingroup\$ Excellent and very thorough answer, thank you \$\endgroup\$
    – Christian
    Commented Oct 7, 2023 at 13:32
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why when we measure the voltage from a magnetic loop antenna are we not measuring the time differential of the magnetic field rather than the magnetic field directly?

We are observing the time differential of the magnetic field, not the static field.

Otherwise, an inductor statically lying next to a magnet (or just in earth's magnetic field) would have a voltage. That's not the case.

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    \$\begingroup\$ I am thinking about the electric field equivalent: a dipole antenna. The for a time varying electromagnetic field, voltage measured on this is directly proportional to the E field at a point in time, whereas for the loop antenna it seems to be proportional to the rate of change of the magnetic field rather than its magnitude. Does this mean all loop antennas are actually differential sensors? \$\endgroup\$
    – Christian
    Commented May 15, 2023 at 14:43
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    \$\begingroup\$ yes. Maxwell does not lie. \$\endgroup\$ Commented May 15, 2023 at 15:02
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    \$\begingroup\$ @Christian dipoles also measure differential. A dipole in a static field will see a sustained voltage, which you can't see, but not a sustained current, which you can see. \$\endgroup\$ Commented May 15, 2023 at 16:03
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    \$\begingroup\$ @Christian A static E field will induce a static potential in the antenna and in any other conductive body. The problem is that electrostatic induction doesn't work the same as the EM induction (Faraday's law). \$\endgroup\$ Commented May 15, 2023 at 18:43
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    \$\begingroup\$ @Christian when you apply a static E field to a conductor, there is a brief period of time where the charges in the conductor move (so you have transient currents), but since E is static, the charges in the conductor will finally stop and reach a state of equilibrium (so no more current after the equalization transient). You will "see" induced static charges on the conductor, but no currents. \$\endgroup\$ Commented May 15, 2023 at 18:47

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