0
\$\begingroup\$

I have the following circuit and I want to varry V1 from 24V to 0v while keeping V2 = 5V, naturally I tried using DC sweep simulation with start value of 24V, end value of 0V and variation of -1, but that gave a variation from 0V to 24V, I've tried changing the variation to 1, that gave the same results.

So my question is : how can I make DC sweep simulation with negative variation? I am using pspice with orcad 16.4

enter image description here

\$\endgroup\$
  • \$\begingroup\$ How can you tell which order the sweep was done? If you're just looking at a graph, of course 0 V is still on the left of the x-axis and 24 V is on the right, even if the sweep was done the other way. \$\endgroup\$ – The Photon May 21 '17 at 19:14
  • \$\begingroup\$ @ThePhoton I deduced from the current curve, since I'm using a thyristor it should switch to off once the current goes below the holding current (At 24v it's already turned on) \$\endgroup\$ – Ernest Dujo May 25 '17 at 11:14
0
\$\begingroup\$

Try varying voltage V1 in Eg: -10 to 24 with the increment of 1. Since there is a increment it should always be increasing. This will increment form -10 in step of 1 till 24. Simulation Settings

\$\endgroup\$
  • \$\begingroup\$ OP wants decreasing, not increasing. The increment must be negative, and then the simulator needs to correctly interpret that and allow a decreasing sweep. \$\endgroup\$ – a concerned citizen May 26 '20 at 10:43
  • \$\begingroup\$ Thanks for correcting me. I will delete the answer since it misguides/ makes no sense. \$\endgroup\$ – Pai May 26 '20 at 17:45
  • \$\begingroup\$ First try to see if it actually works with negative increment. If it does, then it's an answer like any others. \$\endgroup\$ – a concerned citizen May 26 '20 at 18:03
0
\$\begingroup\$

This might not be OP's exact requirement, however, it will work just as fine: instead of a DC sweep use a TRAN analysis, with V1 set as a decreasing ramp, e.g. PWL 0 24 1 0. PULSE() will work, too. Then simply replace time with another quantity after the simulation has run, e.g. I(V2).

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.