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The wiki article explaining inductor core saturation talks about magnetic domains lining up with the external magnetic field to concentrate the magnetic flux. This sounds similar to electric permittivity where dipoles rearrange themselves to cancel internal electric fields.

I know that electric permittivity is frequency dependent since the electric dipoles have inertia and cannot realign themselves instantly.

Is this the case for magnetic permeability (inductor saturation)? If an inductor is claimed to saturate at 750mA in its datasheet, would it be less if the current was AC?

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  • \$\begingroup\$ No. What frequency you used to push the core to saturation, via voltage-time area in your transformer configuration or current-inductance products in inductor configuration does not matter. You still saturate it. If you talk about inductor and DC, it's still just the peak, DC, DC+ACpeak or just ACpeak. \$\endgroup\$
    – winny
    Commented Sep 20, 2017 at 15:43
  • \$\begingroup\$ Is there anything left you need explaining or can this question and the most appropriate answer be accepted formally? \$\endgroup\$
    – Andy aka
    Commented Jan 23, 2019 at 20:44

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Flux density = \$\mu\$H where \$\mu\$ is the magnetic permeability of the core material and H is the applied magnetic field in units of amp-turns per metre. If the turns stay the same and the amps peak at the same value and the core doesn't magically change its dimensions then H remains constant so, providing \$\mu\$ remains constant, peak flux density remains constant.

However, \$\mu\$ will tail-off at higher frequencies and this will mean less flux density.

What you might be thinking of is a coil driven with an AC voltage - that coil has inductance and therefore magnetization current it takes is inversely proportional to frequency hence, for a ferrite core, current falls as frequency rises and this means H falls with frequency and is the whole reason why SMPSs can have quite small transformers yet still be rated at (say) 100 watts.

The big deal here is avoidance of core saturation.

Also, a fairly big deal with laminated transformers is that as you raise frequency there are greater eddy currents circulating in the laminates and, to avoid this, laminates become thinner and thinner and ultimately, you are left with ferrite or a powdered iron core as the only option other than air..

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  • \$\begingroup\$ In order to prevent saturation from being reached, is it sufficient that one stays away from that electric current level where saturation is reached? \$\endgroup\$
    – quantum231
    Commented Sep 17, 2023 at 23:11
  • \$\begingroup\$ Having fewer turns or less current reduces saturation. \$\endgroup\$
    – Andy aka
    Commented Sep 18, 2023 at 6:38
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The saturation itself is AFAIK not frequency dependent (though I am not 100% sure, ferrites have all kind of weird properties when the operation frequency increases). What you definitely get is that the permeability decreases and the loses increase. Which means, your inductor will behave slightly different if you go up in frequency. Depending on the exact core material used, this change can be quite abrupt and can cover several orders of magnitudes.This will make your inductor behave like a non-linear element if you get close to that frequency. If you know what kind of core material has been used, you can check the manufacturers datasheet. To get an idea how ferrites behave, you can have a look at the catalogs of Fair-Rite or TDK, which contain quite a bit of data.

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