This is a followup from a previous question: Analysing signal unbalancing stage which was quite broad as it encompassed couple of things, but answer there pointed me in the right directions so I'm able to pursuit further.

However, one particular thing is still a mystery to me:


The In+ and In- are voltages of the balanced audio line signal (https://en.m.wikipedia.org/wiki/Line_level) - meaning 600Ohms impedance and +4dBu level. What's the role of the capacitors? The answer to previous question suggests it is to block RF signal, so how do that work?

As far as my knowledge goes, those caps provide hi-impedance path to ground for the audio signal (the combined reactance for both input lines would be around 42pF, which, for the audio range would provide reactance of 190M to 190K), so only the negligible amount of signal would go that path (not sure what reactance the transformer coils provide, but probably small compared to the caps). If we take it that it's supposed to act as a shield against RF, then what would be the theoretical basis for that and how would that work? The reactance for RF frequencies would be much lower so they'd be shorted? But isn't the noise cancelled anyway because In+ and In- are inverted polarity, so noise inducted along the cable is cancelled (we sense the voltage difference between those).

The broader context:

I'm analysing a particular schematic, an audio compressor: https://www.soundskulptor.com/en/proddetail.php?prod=LA502

The schematic is here: https://www.soundskulptor.com/docs/la502-schematic-03.pdf

  • 1
    \$\begingroup\$ If the previous question was answered then why haven't you formally accepted an (or the) answer? If questions are still not 100% answered from the previous post then why have you reposted them here? If this is a brand new question and not covered in the previous post then you need to supply technical details about what the input connects to so that the reasons for the capacitors can be determined. \$\endgroup\$
    – Andy aka
    Commented Nov 14, 2020 at 10:44
  • \$\begingroup\$ Yeah, I wanted to wait a bit before accepting but since I've extracted more specific question out of it, there is no reason to address the former. I'll mark it. \$\endgroup\$
    – Bartosz
    Commented Nov 14, 2020 at 10:56
  • 3
    \$\begingroup\$ Your above question still needs context to avoid speculation. The reason why someone added them could easily be based on ignorance (quite often the case) or, it depends on what we don't see and, what we don't see is what isn't included as detail in your question. This means it's unanswerable in its current form. My guess is ignorance (because it happens quite often; i.e. someone tries them and it solves some undisclosed problem but, if they build it again, it wouldn't solve that problem and would probably make it worse). So, context is needed.... what is to the left of the three capacitors. \$\endgroup\$
    – Andy aka
    Commented Nov 14, 2020 at 11:36
  • \$\begingroup\$ Sorry - I'm not sure I can provide more details as to what already is stated because it's some standard audio specs (linked in the original question). What I know: both In+ and IN- carry audio signal, IN- has inverted polarity. The level would be +4dBu, so around -1.7V to +1.7V. the input is just output from some other device, like a microphone preamplifier. The signal is balanced to remove unwanted noise from long cable runs. I was reluctant to add more details other than the link not because I'm lazy, but I could confuse something and it wouldn't help the case:) Sorry for that. \$\endgroup\$
    – Bartosz
    Commented Nov 14, 2020 at 12:13
  • 1
    \$\begingroup\$ Clarified (added some detail) in other answer. \$\endgroup\$
    – user16324
    Commented Nov 14, 2020 at 14:28

2 Answers 2


What's the role of the capacitors?

The two 470 pF are in series across the line so, ignoring the 47 pF capacitor, the two 470 pF act together as a single capacitor of value of 235 pF. This is commonly used and, it ensures that any RF pickup on the cable that might otherwise feed into the transformer (as a differential signal) is largely "shorted" to both lines.

In other words, any slightly imbalanced common-mode RF pick up is reduced differentially and both inputs to the transformer only receive a fraction of the differential RF noise that would be passed to the transformer output should the two capacitors be not present.

That's what the two 470 pF capacitors do. That much is clear.

The added 47 pF capacitor degrades the ability of the two 470 pF capacitors to reduce differential noise because, any slight tolerance difference between the two 470 pF means that the 47 pF WILL create a differential RF signal from a true common mode RF signal.

So, my belief is that the 47 pF could be an error of judgement on the designer's part but, without knowledge of the designer's intent, this is just a guess.

Another guess - the prevailing RF common mode noise on the input side is so high that the 47 pF reduces that noise by many, many decibels. In doing so, the CM noise coupled via the transformer interwinding capacitance (from primary to secondary) is reduced by a decent amount.

  • \$\begingroup\$ Thanks for the answer. (I care more about the first part now, leaving tricky 47p cap behind). What I'd like to find out is bit more of the principles behind it. Is it because such capacitor (with capacitance value selected for given application) acts as a high impedance path for desired frequencies and low impedance path for unwanted ones? Meaning the signal with desired frequency range will "get to " the output (voltage across transformer coil), whereas signal with unwanted frequency will be "shorted " by a capacitor, so the voltage it represents won't be reflected across the coil? \$\endgroup\$
    – Bartosz
    Commented Nov 14, 2020 at 15:50
  • \$\begingroup\$ Basically yes but a capacitor takes current from an input voltage that is based on rate of change of voltage hence, the faster the rate of change of voltage, the more current it takes. \$\endgroup\$
    – Andy aka
    Commented Nov 14, 2020 at 15:52

Here's how I see it:

If In+ and In- both jump up and down simultaneously (known as common-mode noise), common-mode current would equally would flow through capacitors C1/C2 AND C5 towards GND.

If no common-mode noise is present, but differential mode noise (flowing from In+ to In-) in a frequency much higher than the audio frequency (20Hz-20kHz), this noise is filtered through C1 and C2, but NOT C5.

Given the transformer T1, EVERYTHING on its input side is transferred to its output side, i.e. both the audio and the higher frequency differential mode noise. U1b is a single ended OP amp, with its input referenced to secondary GND. Hence common-mode noise and differential-mode noise from the primary side of T1 would be amplified as well.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.