1
\$\begingroup\$

I got an exam tomorrow and I'm still confused with something. I'm sure most people are familiar with the general equation of Amplitude Modulation.

AM(t) = (Ac+m(t))cos ωc t

I found that there is another variant of which cosine is changed with sine.

AM(t) = (Ac+m(t))sin ωc t

And this also applied to both c(t) and m(t) somehow. My thought is that both can be used and it just depends on the waveform/equation given in questions. In my class we used only the one with cosine, so I never get the explanation for this.

\$\endgroup\$
2
  • 2
    \$\begingroup\$ Funnily enough, if you move the receiver 1/4 wavelength further away from the transmitter, that cosine becomes a sine... \$\endgroup\$
    – user16324
    Commented Jun 17, 2021 at 11:31
  • \$\begingroup\$ Welcome Syahrul, please see this link for how to use MathJax to beautify mathematics on this site. If you click Edit below your question, you can make those formulas look pretty. \$\endgroup\$
    – rdtsc
    Commented Jun 17, 2021 at 12:25

1 Answer 1

0
\$\begingroup\$

You are right, both can be used. The useful information you want to transmit through amplitude modulation is contained within the (Ac+m(t)) expression. So the fact that you use a sine or a cosine doesn't really matter in the end.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.