I have a toggle switch that outputs 5V when it is on. I would like to make the off functionality momentarily pull to 0V and then go back to 5V. So basically the off switch isn't really off, it just sends a short 0V wave and then goes back to 5V.
3
-
\$\begingroup\$ What does the 5V output from the toggle switch do? \$\endgroup\$– Bruce AbbottCommented Jul 14, 2021 at 20:22
-
\$\begingroup\$ You are looking for a "falling edge detector". There are various implementations using discrete logic gates and flip-flops, but as @BruceAbbott is trying to get to, this sounds like an XY problem. \$\endgroup\$– virCommented Jul 14, 2021 at 22:03
-
\$\begingroup\$ The output runs to the RST pin on an ESP8266. The switch is basically to wake it up from a deep sleep. The ESP8266 is pretty limited on how it can wake from deep sleep. In reality, it won't be a switch but a lid being removed that turns off the circuit and causes the ESP8266 to wake. I didn't want to wait for the lid to be put back on before waking up. \$\endgroup\$– GatorCommented Jul 15, 2021 at 14:15
Add a comment
|
1 Answer
\$\begingroup\$
\$\endgroup\$
It looks like a falling edge circuit is the right direction. Thank you vir.
I am actually going to switch chips to the ESP32-S2-MINI-1, since it is cheaper than an 8266 and it's possible to wake from deep sleep from GPIO inputs.