0
\$\begingroup\$

enter image description here

In a MOS system, is the energy offset between metal/oxide or semiconductor/oxide always the same regardless of the gate voltage applied? In other words, are A and B in the diagram above always the same? I think the offset must be always the same since it is determined by the material property (difference between work function of the material), but I see people draw this band diagram under bias as if these offsets change.

\$\endgroup\$

1 Answer 1

0
\$\begingroup\$

A is always the same because it depends only on the metal..oxide work function.i B depends on the accumulation/depletion at the oxide..semconductor interface, so changes (until there is accumulation).

The slope through the oxide changes with applied V, so the amount by which B is above A changes.

In addition, as the V changes, the semiconductor part's depletion region widens, or thins to just an accumulation layer. The curved part in the semiconductor will change with those conditions.

\$\endgroup\$
1
  • \$\begingroup\$ Gotcha, so is B equal to the difference in electron affinity between the oxide and the bulk semiconductor plus the surface potential (amount of total band bending)? \$\endgroup\$
    – user207787
    Commented Nov 24, 2021 at 14:44

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.