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I'm currently comparing characteristics of some different amplifiers, specifically their CMRR, and I came across this amplifier, which rather than listing an explicit CMRR, merely says:

Maximum Common Mode 1.2 V

As it is, I can't find a CMRR listed anywhere on the website, is this an equivalent statement for CMRR? If so, how would I calculate an equivalent CMRR from this seemingly uninformative statement? I've done a google search and a search on here for any information regarding expressing CMRR as a voltage, but so far no luck

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  • \$\begingroup\$ Max common mode I suspect is them saying that differential inputs can be measured accurately in the presence of a + or - 1.2V common mode voltage that might be offsetting the measurement above or below 0V. A lot of instrumentation amps and op-amps call it the common mode input range - how far can you push both inputs from 0V and still get an accurate differential measurment. \$\endgroup\$
    – Andy aka
    Commented Jul 12, 2013 at 10:38
  • \$\begingroup\$ If I remember, CMRR is limited to the rail voltage. One amp design feeds back the Common Mode to cancel itself at the output. \$\endgroup\$ Commented Jul 12, 2013 at 10:42

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That parameter says nothing about the CMRR. All it is telling you is the maximum common mode voltage (\$V_{comm}\$) the amplifier can handle while still meeting the other specifications.

schematic

simulate this circuit – Schematic created using CircuitLab

$$ V_{comm} = \frac{V_+ + V_-}{2}$$

Provided that \$V_{comm} < 1.2V\$ (and really, they probably mean \$-1.2V < V_{comm} < 1.2V\$) then the amplifier will function according to specifications. Ostensibly, this common mode signal is attenuated, but if the CMRR is unspecified, then we don't know by how much.

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