0
\$\begingroup\$

I have some of the information, but a lot of it is missing and I cant find a clear answer on the web.

The general form of a second order dynamic system is:

$$\frac{d^2x(t)}{dt^2}+2\zeta\omega_n\frac{dx(t)}{dt}+\omega_n^2x(t)=f(t)\:\:\:\:\:\:\:[1]$$

where

x(t) - is the output, e.g current
f(t) - is the input, e.g a voltage signal
zeta - is the damping coefficient
wn   - is the natural frequency

An example of a second order dynamic system is a RLC circuit. If a resistor, capacitor, and inductor are connected to a power source with voltage at time t equal to f(t), the summed voltage across the three components always equals f(t) at any time t.

$$Ri(t)+\frac{1}{C}\int_0^ti(t)dt+L\frac{d\,i(t)}{d\,t}=f(t)\:\:\:\:\:\:\:[2]$$

So for example if f(t) is a step input from 0 to 6V, the equation will be:

$$Ri(t)+\frac{1}{C}\int_0^ti(t)dt+L\frac{d\,i(t)}{d\,t}=6\:\:\:\:\:\:\:[3]$$

If this equation is rearranged so that it is in the general form shown in equation [1], then you will be able to find out the natural frequency of the system (omega_n) and the damping coefficient of the system (zeta).

The general form of a first order dynamic system in laplace space is:

$$G(s)=\frac{k(s+a)}{s+b}\:\:\:\:\:\:\:[4]$$

where

G(s) - is the transfer function (output/input)
k    - is the "gain" of the system
a    - is the zero of the system, which partially determines transient behavior
b    - is the pole of the system, which determines stability and settling time 

An example of a first order dynamic system is a RC circuit. The voltage across the resistor plus the voltage across the capacitor equal the voltage of the source f(t) at any time t.

$$Ri(t)+\int_0^ti(t)dt=f(t)\:\:\:\:\:\:\:[5]$$

So again, for a step input from 0 to 6V, the equation will be:

$$Ri(t)+\int_0^ti(t)dt=6\:\:\:\:\:\:\:[6]$$

In laplace space this is

$$RI(s)+\frac{1}{Cs}I(s)=\frac{6}{s}\:\:\:\:\:\:\:[7]$$

rearrange to general form:

$$I(s)*(Rs+\frac{1}{c})=6\:\:\:\:\:\:\:[8]$$

$$I(s) =\frac{6}{Rs+\frac{1}{c}}\:\:\:\:\:\:\:[9]$$

$$I(s) =\frac{\frac{6}{R}}{s+\frac{1}{Rc}}\:\:\:\:\:\:\:[10]$$

Since the input was the step input 6, you can see that the steady state gain is equal to 6/R, the pole is equal to 1/RC, and there are no zeros. You could do the inverse laplace transform of this equation to find out the instantaneous current i(t) at any time t.

Now my questions:

  • I have shown the general form of a first order dynamic system in laplace space, and the general form of a second order dynamic system in time space, but what is the general form of a first order system in time space, and a second order system in laplace space? I have definitely seen these written somewhere but I can't find them in my notes or online.

  • How would you go from equation [3], to the general form (time space) as shown in equation [1]?

Any answer is much appreciated, even if it only answers one of the questions, or partially answers a question. Thanks for reading!

\$\endgroup\$
2
  • \$\begingroup\$ Check your first question - there seems to be a contradiction on the 2nd order part. \$\endgroup\$
    – Andy aka
    Commented Apr 11, 2014 at 22:20
  • \$\begingroup\$ I don't understand the first order example. Why does one have a the zero \$(s+a)\$ and the other does not? \$\endgroup\$
    – SomeEE
    Commented Apr 12, 2014 at 5:03

1 Answer 1

1
\$\begingroup\$

You want to use the following property of Laplace transform: $$\mathscr{L}\left({\frac{dx(t)}{dt}}\right)(s) = s\mathscr{L}\left(x(t)\right)-x(0)$$

This allows you to easily move between differential equations and polynomial equations.

Time domain to frequency domain: Take your first equation for example $$\frac{d^2 x(t)}{dt^2} + 2 \zeta \omega_n \frac{dx(t)}{dt} + \omega_n^2 x(t) = f(t).$$

If we denote the Laplace transform of \$x(t)\$ by \$X(s)\$ and \$f(t)\$ by \$F(s)\$ and apply Laplace transform to this equation then this property implies $$s^2 X(s) + 2 \zeta \omega_n sX(s) + \omega_n^2 X(s) = F(s)$$ where for simplicity I assume that \$x(0) = f(0) = 0\$.

The transfer function is defined as the ratio: $$\frac{X(s)}{F(s)} = \frac{1}{s^2+2 \zeta \omega_n s + \omega_n^2}$$

Frequency domain to time domain: Lets try the example \$G(s)=\frac{1}{s^3+1}\$ then we have by definition that $$G(s)F(s) = X(s)$$ which implies $$F(s) = s^3X(s)+ X(s).$$

Taking inverse Laplace transform we find that $$f(t) = \frac{d^3 x(t)}{dt^3} + x(t).$$

Hopefully this allows you to see the pattern in general.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.