Suppose we have an electric field $$E_x(z) = E^+e^{-\gamma z} + E^-e^{\gamma z}$$ where $$\gamma=\alpha+j\beta$$ is the complex propagation propagation constant, as defined in David Pozar's Microwave Engineering Section 1.4. The propagation factor then has form (in the time domain): $$e^{-\alpha z} \cos(\omega t - \beta z)$$ which represents a wave traveling in the +z direction.
From this, the skin depth is defined as $$\delta_s = \frac{1}{\alpha}$$ which is of course the distance that the wave travels in the +z direction over which it decays by 1/e.
This makes sense to me if we have an external wave incident upon a metal plate. Clearly, its depth of penetration is limited by the skin depth.
However, suppose instead that I have a wire (part of a simple voltage source + resistor circuit) carrying a sinusoidal current. Say this particular wire is oriented in the +z direction. Then the electric field wave is also oriented in the +z direction (J=σE). Would this not imply that after travelling one skin depth, my current is attenuated by 1/e? That obviously makes no sense:
- It would imply that transmitting a non-dc current is effectively impossible as it just gets attenuated right away.
- Typically, we see skin depth in a round conductor as creating a sort of 'donut' shaped conductor at high frequencies, which clearly does not align with whatever I'm picturing.
I suppose I must have a fundamental misunderstanding in the direction of the various components, and hope somebody can clear it up for me.