# Applying KVL to this circuit

In my Circuit Analysis book, I am tasked with finding $v_x$ and $v_y$. So $v_y$: easy enough. It's - 6 volts. But I encounter a problem when trying to find $v_x$ - I can't develop enough independent equations to solve for all of the elements in a given loop.

Of the components in series, I called the topmost one $v_c$ and the lower one $v_b$. I called the rightmost component $v_a$.

$$-21+7+v_x+v_a=0\\ v_x-14+v_c+v_b=0\\ -v_b-v_c+v_a=0\\ -21+7+v_x+v_c+v_b=0\\$$

Sadly, I can show at least to of these to be the same equation (they are not indepenet of each other!) so I have literally no idea how to solve this.

This is only the second problem of this type I have ever tried to solve, that I remember.

I would really appreciate it if someone could get me out of this jam!

The book gives the answer to be 9 volts.

• Well, there is several notable things about this question. 1) 21-7 != -6 2) these blocks in the diagram serve an unknown function, are they voltage sources? are they resistors? 3) most notably, there is not enough information here to determine $V_x$. – placeholder Sep 15 '14 at 14:39
• Not enough information? Thank god. That's what I thought. If you can prove this, I'll gladly accept it as an answer. – user1833028 Sep 15 '14 at 15:49
• What do the "1" and "0" mean in the diagram? Are the just node numbers? Without component values or voltages or currents for these three elements on the right they could be anything. For example, if the two in series in the center are 0 ohm resistors then they short out node 1 to node 0. If they tend to very large values then the answers depend on their exact values. There must be some text missing from the figure. (oh, and 21V-7V = 14V...) – mixed_signal Sep 29 '14 at 3:22
• Could you type in the complete question found in the book? Perhaps the labels $0$ and $1$ refer to a logic $0$ and a logic $1$, where a logic $1$ is defined to be 5 volts? – Joel Reyes Noche Sep 30 '14 at 1:30