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enter image description here

The circuit which is shown above has no resistance. So there is no time constant. Plus the current source has no resistance in parallel. So I cant convert it into voltage source. Is there any way to find the voltage across the capacitor after 6 seconds?

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    \$\begingroup\$ look here \$\endgroup\$
    – G36
    Commented Jun 15, 2020 at 18:22
  • \$\begingroup\$ oh .. thanks. Didn't think in an easy way :( \$\endgroup\$
    – Sadat Rafi
    Commented Jun 15, 2020 at 18:23

1 Answer 1

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Since this appears to be homework we won't give you a direct answer but guide you through it.

  1. First edit your question to write the equation relating capacitance, charge and voltage.
  2. Hint: current is the rate of flow of electric charge past a point. What mathematical function can you perform on equation 1 to relate the change in voltage as a function of the current and time?

Edit your post with your work and see if that prompts you enough to complete the task.

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  • \$\begingroup\$ There is no possibility of homework. Because I am not studying in anywhere. I got the answer from the comment. Thanks. \$\endgroup\$
    – Sadat Rafi
    Commented Jun 15, 2020 at 18:44
  • \$\begingroup\$ \begin{equation} i_c = \frac{dv}{dt} \end{equation} I assume that you are asking for this. \$\endgroup\$
    – Sadat Rafi
    Commented Jun 15, 2020 at 18:47
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    \$\begingroup\$ You forgot to add in C making it \$ i_c = C \frac {dv}{dt} \$. I'm glad you figured it out. \$\endgroup\$
    – Transistor
    Commented Jun 15, 2020 at 18:50

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