What does a TL062 Op-Amp with output grounded and both inputs connected together with voltage divider mean?

Question

So I'm studying Kilovoltmeters and subsequently using ADC's with resistor arrays and dividers from high voltage power supplies of all varieties.

I've got a good idea as to what they are and how they work, especially in use for SMPSs. However, in my researching I found this weird texas instruments dual-jfet-amp TL062 configuration with amp A being a buffer followed by the other, weirder amp, amp B; this is the main issue here as is described in the title. The power supply is an SMPS with a long chain of Cockcroft-Walton multipliers. The link to the pdf is under the image provided.

The inverting input of B is a 1/2 voltage divider with 100k resistors, and the non inverting input is connected via R2 of the divider and also trails off to an Arduino ADC pin.

I know Op-Amp inputs always want to stay the same if the output is used in a negative-feedback configuration, thus virtual ground, but none of that beautiful op-amp action is seen at amp B :(

I'm thinking the second amp is bogus as it's totally shorted to ground and bypassed straight to the ADC; could potentially release some really nice magic smoke. Inputs would be fine, though!

Pic: https://wiki.jlab.org/cuawiki/images/d/d9/CW-Base_Jan2016_v2.pdf

Any feedback helps!

Answer 1

The schematic doesn't match the layout.

I overlaid the PCB sides and highlighted the connections to pin 5 of the TL062 in black. This shows that pin 5 is actually connected to ground, and pin 7 is the output to the Arduino.

Answer 2

As Bruce Abbott points out, the pin connections on U1B are incorrect. U1B is a simple inverter with a gain of 1 (but very high accuracy.)

Basically, resistor divider chain at the top of the schematic reduces the (negative) cathode voltage to a reasonable value. U1A buffers the divider, and U1B inverts the voltage so as to feed the ADC with a positive voltage.