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schematic diagram

(Image source - Edited from Figure 3 of "SUPERNODE Circuit Analysis | Step by Step with Solved Example")

In the given image why aren't the node voltages of nodes marked 1 and 2 same? There isn't any component between them and they are connected by a wire so shouldn't they be at the same potential?

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  • \$\begingroup\$ That website is semi-insane. In any case, a supernode solution would look like: \$6\cdot V_3+2\cdot\left(V_3+5\right)=13\quad\therefore\:V_3=\frac{3}{8}\:\text{V}=375\:\text{mV}\$. Without using supernodes, it's two equations in two unknowns and the solution is still the same for \$V_3\$. \$\endgroup\$
    – jonk
    Commented Aug 31, 2018 at 5:25

1 Answer 1

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They are at the same potential, and for the purposes of circuit theory they are the same node --- they should not be labelled with two different node names.

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  • \$\begingroup\$ The answer given is node voltage of 1 is 1.708 V and node voltage of 2 is 5.375 V \$\endgroup\$
    – A lotta doubts
    Commented Aug 31, 2018 at 3:33
  • \$\begingroup\$ Are you sure that answer goes with this diagram? Because there are only 2 nodes (other than ground) in this diagram, and they must have 5 V difference between them. \$\endgroup\$
    – The Photon
    Commented Aug 31, 2018 at 3:34
  • \$\begingroup\$ Yes, i can provide the link for the same. \$\endgroup\$
    – A lotta doubts
    Commented Aug 31, 2018 at 3:35
  • \$\begingroup\$ electricaltechnology.org/2015/02/… \$\endgroup\$
    – A lotta doubts
    Commented Aug 31, 2018 at 3:37
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    \$\begingroup\$ It looks like that's just a terrible website. Eq 1 makes no sense at all (where do the factors of 3 in the numerators come from? Why are they dividing by 0?) Why are they resolving division by 0 by setting those terms to 0? Whoever wrote it was very confused. \$\endgroup\$
    – The Photon
    Commented Aug 31, 2018 at 3:41

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