Skip to main content
32 votes
Accepted

Side effects of using large resistances

There are many drawbacks to both low and high values alike. The ideal values will fall in between very large and very small for most applications. A larger resistor of same type will, for example, ...
Asmyldof's user avatar
  • 18.5k
26 votes
Accepted

How negative feedback increases the bandwidth

You have to realize what Bandwidth actually means. Bandwidth is the frequency at which the gain starts to drop when frequency increases. So if lowering the gain (using feedback) moves that point (...
Bimpelrekkie's user avatar
  • 81.4k
18 votes

Side effects of using large resistances

In addition to the issues that @Asmyldof mentions, when using high resistances in the megaohms (and especially at 10M and more) environmental contamination such as dust, skin oils, soldering flux ...
pericynthion's user avatar
  • 6,195
18 votes
Accepted

How does the compensation resistor in an inverting amplifier compensate for the input bias current?

Sample Bipolar Schematic and Behavioral Description Let's look at the LM324. It's a bipolar opamp and it is also a lot easier to follow that some. But it is still fairly representative of the basic ...
jonk's user avatar
  • 78.7k
17 votes
Accepted

Virtual Ground Paradox?

It's #2. For a "perfect" theoretical opamp, the open-loop gain is infinite, and this makes the difference at the inputs zero. When introducing opamp circuits, or when working out how things are ...
Jack B's user avatar
  • 12.3k
14 votes
Accepted

Reason for small-valued feedback resistors in low noise Op Amp

This op-amp boasts input noise of 0.9 nV/√Hz, which is roughly equal to the Johnson noise of a 50 Ω resistor. If you aren't putting resistors smaller than that around it, you're wasting some ...
Warren Young's user avatar
  • 3,762
13 votes
Accepted

Why do we get only one frequency as output in oscillators?

Why do we get only one frequency as output in oscillators? Oscillators work at one frequency by ensuring two things: - The signal fed back to sustain oscillations is exactly in phase with the signal ...
Andy aka's user avatar
  • 473k
13 votes
Accepted

Where do zeroes come from in a circuit?

Q1a There is a direct connection from input to output without passing through the dynamics of the system. Output is directly influenced by the input. Q1b It is a feedback path as as well as feed-...
AJN's user avatar
  • 3,911
13 votes
Accepted

How does a unity gain buffer work?

You've applied the non-idealities of the op amp inconsistently, and have reached a false contradiction. In particular, you've assumed that the op amp has infinite open-loop gain when you concluded ...
nanofarad's user avatar
  • 20.6k
13 votes

Why are these voltage regulators seemingly using positive feedback?

You must consider the whole feedback, not just the error amplifier but also the transistor. It is the transistor that adds a 180° shift, which changes positive feedback into negative.
Hyp's user avatar
  • 1,029
12 votes
Accepted

Which CMOS logic families can safely be used to construct linear circuits?

All logic families like to use buffered inverters, because those are more reliable and use less power in digital applications. However, unbuffered inverters are useful to build crystal oscillators, so ...
CL.'s user avatar
  • 20.1k
12 votes
Accepted

Sziklai pair feedback loop

I have illustrated much of what was said in the answers and comments above and expanded it by some of my thoughts. 1. Compound transistor. The n-p-n and p-n-p transistor connected in this way form a ...
Circuit fantasist's user avatar
11 votes
Accepted

Why would you use a feedback resistor on a logic buffer?

The resistor adds additional hysteresis beyond what the chip provides. With the nature of what the internet is these days quite possibly you may have found a circuit idea that was designed before the ...
Michael Karas's user avatar
11 votes

Op Amp Feedback Resistors

To a first-order approximation, it's a matter of how much current the op-amp can provide (sets a lower bound on resistance), how much power you can stand to consume (sets a lower bound) how much error ...
Hearth's user avatar
  • 38.5k
10 votes

How does this Push-Pull amplifier work?

Let as exam the BJT push-pull amplifier along first. Any BJT's need at least 0.5V to 0.7V of forward base-emitter bias voltage before they will go into conduction. In push-pull amplifier both of the ...
G36's user avatar
  • 15.7k
10 votes

Virtual Ground Paradox?

Let's just do the WHOLE shebang, start to finish, instead of doing this piecemeal. Let's start with the definition for the op amp. $$ V_{out}= A_{OL}(V_+ - V_-)$$ As has been pointed out, \$A_{OL}\$...
Scott Seidman's user avatar
10 votes
Accepted

How do I explain this regulation action in terms of control theory?

There is no closed loop feedback system evident That's because you didn't spot it. It's the base-emitter region of the 2N3904 (Q2) that acts like a comparator at around 0.5 volts to 0.7 volts (...
Andy aka's user avatar
  • 473k
9 votes
Accepted

Input stage of a current mirror circuit

There are many different BJT models, with varying degrees of usefulness in varying circumstances. (See SIDEBAR at bottom.) I'm not going to delve into any of that as it's not necessary in this case. A ...
jonk's user avatar
  • 78.7k
9 votes

Virtual Ground Paradox?

The problem is that you mix-up two different models of the op-amp. A real, but somewhat idealized op-amp, is a differential amplifier whose output depends on the inputs as follows (neglecting ...
LorenzoDonati4Ukraine-OnStrike's user avatar
9 votes
Accepted

Voltage regulator frequency range

Neither. You should use a potential divider: simulate this circuit – Schematic created using CircuitLab edit: Just to add, this will give a 0-4V wave at 24Vin, and a 0-2V wave at 12Vin. This ...
BeB00's user avatar
  • 5,611
9 votes
Accepted

Non-inverting op-amp configuration with capacitor

A lot of times I hear that it's useful for stability but I don't get why and how to calculate it's value. Consider that the non-inverting pin might have a parasitic capacitance of maybe 4 pF. That'...
Andy aka's user avatar
  • 473k
9 votes
Accepted

Changing output voltage of a buck converter by electronically swapping the feedback resistors

Two things. First, use two FETs and two wires to control them instead of 3, and second, use a resistor-ladder approach. You have three low-side resistors, R2a,b,c. Wire them in series, then use the ...
hacktastical's user avatar
  • 58.4k
9 votes

What does "Brushless DC is an AC induction motor with built-in speed feedback" mean?

It means the poster doesn't know the difference between an induction machine and a synchronous machine, nor do they know the range of DC brushless motors out there. Having waxed cynical: the term "...
TimWescott's user avatar
  • 47.1k
9 votes
Accepted

DC Gain of the System

What you need to stabilize your converter is the control-to-output transfer function: if a stimulus is applied to the duty ratio input, how does it propagate through the converter and create a ...
Verbal Kint's user avatar
  • 23.5k
9 votes

How does the compensation resistor in an inverting amplifier compensate for the input bias current?

In short, every op-amp has a differential amplifier at the input. Thus, every transistor needs a "base" current (input bias current) to flow to work as the amplifier. So for example in the ...
G36's user avatar
  • 15.7k
9 votes
Accepted

Voltage regulation feedback loops

If we ignore the PWM and switching elements for the moment, here's what the system looks like: simulate this circuit – Schematic created using CircuitLab Your implication that the TL431 ...
Simon Fitch's user avatar
  • 47.2k
8 votes
Accepted

Block diagrams can be different and still works for the same system?

Your answer is incorrect in the sense that you produce an error signal from signals that have different physical dimensions. In your system, you subtract temperature units from volts, which is not a ...
Vicente Cunha's user avatar
8 votes

Non-inverting op-amp configuration with capacitor

Just to add a bit to Andy's answer (a mathematical approach). In order to understand why, you need to be familiar with the frequency response. An opamp has input and stray capacitance on the inputs, ...
Big6's user avatar
  • 5,784

Only top scored, non community-wiki answers of a minimum length are eligible